3/(2x)-x/(4x^2-1)=7/(4x+2)

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Solution for 3/(2x)-x/(4x^2-1)=7/(4x+2) equation:


D( x )

4*x+2 = 0

4*x^2-1 = 0

2*x = 0

4*x+2 = 0

4*x+2 = 0

4*x+2 = 0 // - 2

4*x = -2 // : 4

x = -2/4

x = -1/2

4*x^2-1 = 0

4*x^2-1 = 0

4*x^2 = 1 // : 4

x^2 = 1/4

x^2 = 1/4 // ^ 1/2

abs(x) = 1/2

x = 1/2 or x = -1/2

2*x = 0

2*x = 0

2*x = 0 // : 2

x = 0

x in (-oo:-1/2) U (-1/2:0) U (0:1/2) U (1/2:+oo)

3/(2*x)-(x/(4*x^2-1)) = 7/(4*x+2) // - 7/(4*x+2)

3/(2*x)-(x/(4*x^2-1))-(7/(4*x+2)) = 0

3/(2*x)-(x/(4*x^2-1))-7*(4*x+2)^-1 = 0

(-1*x)/(4*x^2-1)-7/(4*x+2)+3/(2*x) = 0

(-1*2*x*x*(4*x+2))/(2*x*(4*x^2-1)*(4*x+2))+(-7*2*x*(4*x^2-1))/(2*x*(4*x^2-1)*(4*x+2))+(3*(4*x^2-1)*(4*x+2))/(2*x*(4*x^2-1)*(4*x+2)) = 0

3*(4*x^2-1)*(4*x+2)-1*2*x*x*(4*x+2)-7*2*x*(4*x^2-1) = 0

48*x^3-64*x^3-4*x^2+24*x^2+14*x-12*x-6 = 0

20*x^2-16*x^3+2*x-6 = 0

20*x^2-16*x^3+2*x-6 = 0

2*(10*x^2-8*x^3+x-3) = 0

10*x^2-8*x^3+x-3 = 0

{ 1, -1, 3, -3 }

1

x = 1

10*x^2-8*x^3+x-3 = 0

1

x-1

2*x-8*x^2+3

10*x^2-8*x^3+x-3

x-1

8*x^3-8*x^2

2*x^2+x-3

2*x-2*x^2

3*x-3

3-3*x

0

2*x-8*x^2+3 = 0

DELTA = 2^2-(-8*3*4)

DELTA = 100

DELTA > 0

x = (100^(1/2)-2)/(-8*2) or x = (-100^(1/2)-2)/(-8*2)

x = -1/2 or x = 3/4

x in { -1/2, 3/4, 1}

2*(x+1/2)*(x-3/4)*(x-1) = 0

(2*(x+1/2)*(x-3/4)*(x-1))/(2*x*(4*x^2-1)*(4*x+2)) = 0

(2*(x+1/2)*(x-3/4)*(x-1))/(2*x*(4*x^2-1)*(4*x+2)) = 0 // * 2*x*(4*x^2-1)*(4*x+2)

2*(x+1/2)*(x-3/4)*(x-1) = 0

( x+1/2 )

x+1/2 = 0 // - 1/2

x = -1/2

( x-1 )

x-1 = 0 // + 1

x = 1

( x-3/4 )

x-3/4 = 0 // + 3/4

x = 3/4

x in { -1/2}

x in { 1, 3/4 }

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